In measuring the sides of a rectangle errors of 5 % and 3 % in excess are made. The error percent in the calculates area is_________?

Explanation:

Let length = x units and breadth = Y units

Then actual area = xy sq.units

Length shown = (105/100 × x)units = 21x/20 units;

Breadth shown = (103/100 × Y)

Calculated area = (21x/20 × 103y/100)sq.units

= 2163xy/2000 sq.units

Error = (2163xy/2000 – xy)

= 163xy/2000

Error % = (163xy/2000 × 1/xy × 100)%

= 163/20 % = 8.15 %